The molecular weight of carbon dioxide is 44. According to Priestley, half this weight was made up by water. Carbon dioxide is known famously by its chemical formula CO2, that is, one volume of carbon (12) added to two volumes of oxygen (32). Water therefore, has the atomic weight of 22.
Mr. David Low, in his book "Simple Bodies of Chemistry" revealed that oxygen was a hydrocarbon, that is, by weight, two parts hydrogen to six parts carbon. Thus, the formula for oxygen (16), where C=6, is H4C2.
When creating the formula for water, it is essential to know that the value for C is 3. This being the case, then the atomic weight of water (22) has to be made up by two halves of 11. The formula for water (11), where C=3, is H2C3.
If we look at the formula for carbon dioxide again, one volume of carbon plus two volumes of oxygen, where C=3, it might be something like this:
Carbon + Oxygen + Oxygen = C4 + H4C4 + H4C4
On the other hand, the formula for water is H4C6, so it would appear that the carbon in carbon dioxide is equally distributed amongst the oxygen, as shown below:
C4 + H4C4 + H4C4 = H4C6 + H4C6
In a previous post, I discussed that it was helium, and not hydrogen, which is the first "atom". A hydrogen ion, or proton, is one half of the atom, and then an electron is making up the other half. When brought together, the proton and electron form dipolar vortices, like that of a vortex ring. I think that a hydrogen ion acts out cyclonic behaviours, while the electron is anticyclonic. Both are structures in the aether, so both are essentially created from the electric fluid, it's just that the hydrogen ion exhibits a lack of of the fluid, while the electron has an excess.
I think the fluid of the aether is made up with something which I can only describe as vaporized carbon. If hydrogen is empty, it could therefore be seen that the electron is the component which contained the carbon.
If the formula for a half volume of water is H2C3 (11) for half volume, and we were thinking of breaking it down to reveal the weight of a water atom, we might start by assuming there are two parts hydrogen, or two hydrogen ions. We could interpret the hydrogen ions as signifying the presence of 2 water atoms. If we share the carbon amongst the atoms, we find that one water atom, by weight, consists of 1 part hydrogen and 4.5 parts carbon.
So, in the case of helium, with the atomic weight of 2, we have one part hydrogen and one part electron. Can we dare to suppose then, that an electron's atomic weight is made up by carbon? Thus, the immediate difference to emerge between the atoms of helium and water, is that a water atom is more saturated by carbon.
Oxygen on the other hand is made up by two parts hydrogen and six parts carbon, and has the formula H4C6 (C=3). Therefore, an oxygen atom could be represented, at least by weight, as 1 part hydrogen, and 3 parts carbon.
The comparison I am most drawn to is the size of the atom in DECOMPOSED water, and in COMPOSED water. The formula for decomposed water (9) is something like:
Hydrogen + Oxygen = H + H2C2
The carbon component of the oxygen atom has a value of 3 . That means that when the oxygen is composed into a water atom, it is fattened up on carbon to the value of 4.5 .
Thus far, it seems that a conspicious value for carbon, in the construction of atoms, is 1.5 .It could be interpreted that carbon is present in multiples of 1.5 . At this stage, it remains to be seen why the value for the electron (assuming it is carbonic) , as in the case of helium, appears to be only 1.